问题
选择题
设函数f(x)=
|
答案
根据题意,得
f(x)dx=∫ e0
x2dx+∫ 10 ∫ e1
dx1 x
=
x31 3
+ln| 10
=(x| e1
×13-1 3
×03)+(lne-ln1)1 3
=
+1=1 3 4 3
故选:D
设函数f(x)=
|
根据题意,得
f(x)dx=∫ e0
x2dx+∫ 10 ∫ e1
dx1 x
=
x31 3
+ln| 10
=(x| e1
×13-1 3
×03)+(lne-ln1)1 3
=
+1=1 3 4 3
故选:D