问题
填空题
设f(x)=
|
答案
∫02f(x)dx
=∫01f(x)dx+∫12f(x)dx
=∫01(x2)dx+∫12(2-x)dx
=
x3|01+( 2x-1 3
x2)|121 2
=
+4-2-2+1 3
=1 2
.5 6
∴∫02f(x)dx=
.5 6
故答案为:5 6
设f(x)=
|
∫02f(x)dx
=∫01f(x)dx+∫12f(x)dx
=∫01(x2)dx+∫12(2-x)dx
=
x3|01+( 2x-1 3
x2)|121 2
=
+4-2-2+1 3
=1 2
.5 6
∴∫02f(x)dx=
.5 6
故答案为:5 6