问题
选择题
设向量
|
答案
由|
|=1,|a
-a
|=b
可得3
2+a
2-2b
•a
=3,即b
2-2b
•a
=2.b
再由
•(a
-a
)=0 可得 b
2-a
•a
=0,故有b
•a
=1,b
2=4.b
∴|2
+a
|=b
=(2
+a
)2b
=24
2+4a
•a
+b
2b
,3
故选C.
设向量
|
由|
|=1,|a
-a
|=b
可得3
2+a
2-2b
•a
=3,即b
2-2b
•a
=2.b
再由
•(a
-a
)=0 可得 b
2-a
•a
=0,故有b
•a
=1,b
2=4.b
∴|2
+a
|=b
=(2
+a
)2b
=24
2+4a
•a
+b
2b
,3
故选C.