若关于x的方程x2+（m-3）x+m=0的两个实数根是不相等的正数，则实数m的取值范围是______．
若关于x的方程x2+（m-3）x+m=0的两个实数根是不相等的正数，
即x1＞0，x2＞0，且x1≠x2，
则△=(m-3) 2-4m＞0 x 1+x 2=3-m＞0 x 1•x 2=m＞0
解得0＜m＜1
故实数m的取值范围是（0，1）
故答案为：（0，1）
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