问题
解答题
解方程：
（1）8（x-1）3=27
（2）3（2x+1）2-48=0．
答案
（1）系数化为1得：（x-1）3=
，27 8
开立方得：x-1=
，3 2
解得：x=
．5 2
（2）移项得：3（2x+1）2=48，
系数化为1得：（2x+1）2=16，
开平方得：2x+1=±4，
x1=
，x2=-3 2
．5 2
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解方程：
（1）8（x-1）3=27
（2）3（2x+1）2-48=0．
（1）系数化为1得：（x-1）3=
，27 8
开立方得：x-1=
，3 2
解得：x=
．5 2
（2）移项得：3（2x+1）2=48，
系数化为1得：（2x+1）2=16，
开平方得：2x+1=±4，
x1=
，x2=-3 2
．5 2
| 从下面方框中选择适当的单词或短语,并用其正确形式填空 。 | |
2. He could not _____ his absence from school. 3. Please _____ me to leave for a few minutes. 4. The thief was caught _____. 5.It doesn't seem ugly to me; _____, I think it's rather beautiful. 6. They all _____ the little boy with surprise. 7. ____ and do what you like. 8.I found the map _____ when I was cleaning the room. |