问题 问答题

(1)物体与接触面间的动摩擦因数μ=?

(2)AB之间的距离sAB=?

答案

(1)0.58(2)10 m

(1) 物体在斜面上恰能匀速下滑,平行于斜面方向上的合力为零,则

mgsin30°=μmgcos30°                                                           ①

μ=="0.58··························································" ②

(2) 设物体从AB的运动过程中加速度大小为a1BC的运动过程中加速度大小为a2,则

Fμmgma1··············································· ③

μmgma2··················································· ④

解得a1 m / s2······································ ⑤

a2=10 m / s2

根据题意有····· ⑦

所以········································· ⑧

sAB=10 m···················································· ⑨

评分标准:本题共12分,其中①③④式各2分,②⑤⑥⑦⑧⑨式各1分。

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