问题 解答题
递等式计算
578-405÷45×16(46+165÷55)×83[96-(42+36)]×19
15×[(45-15)÷3][(325+175)÷5]÷2533×20+560÷70.
答案

(1)578-405÷45×16,

=578-9×16,

=578-144,

=434;

(2)(46+165÷55)×83,

=(46+3)×83,

=49×83,

=4067;

(3)[96-(42+36)]×19,

=[96-78]×19,

=18×19,

=342;

(4)15×[(45-15)÷3],

=15×[30÷3],

=15×10,

=150;

(5)[(325+175)÷5]÷25,

=[500÷5]÷25,

=100÷25,

=4;

(6)33×20+560÷70,

=660+8,

=668.

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