问题
解答题
已知向量
(Ⅰ)若
(Ⅱ)若
(Ⅲ)若
|
答案
(1)∵
=(m,-1),. a
=(. b
,1 2
),且3 2
∥a
,b
∴m
-3 2
.(-1)=0,∴m=-1 2
.3 3
(2)∵
=(m,-1),. a
=(. b
,1 2
),且3 2
⊥a
,b
∴
•. a
=0,m•. b
+(-1)1 2
=0,∴m=3 2
.3
(3)∵
⊥. a
,∴. b
•. a
=0. b
由条件可得|
|=a
= 2,|b| =
2+13
=1,[
2+1 2
23 2
+(t2-3)a
]•(-kb
+ta
)=0,b
即:-k
2+(t2-3)ta
2=0,即-k|b
|2+(t2-3)t|a
|2=0,即-4k+(t2-3)t=0.b
∴k=
,由 (t2-3)t 4
=k+t2 t
=t3-3t+4t2 t
(t2+4t-3)=1 4
(t+2) 2-1 4
,7 4
可得当t=-2时,
有最小值-k+t2 t
.7 4