已知|
(1)若
|
(1)设
=(x,y),∵|a
|=3,∴x2+y2=9…①a
又∵
⊥a
∴b
•a
=0即2x+y=0…②…(3分)b
由①②可解得:
或x= 3 5 5 y=- 6 5 5 x=- 3 5 5 y= 6 5 5
∴
=(a 3 5
,-5 6 5
)或(-5 3 5
,5 6 5
)…(6分)5
(2)设
=(x,y)(3),∵|a
|=3,∴x2+y2=9(4)…(5)①a
又∵
∥a
∴x=2y…②…(9分)b
由①②可解得:
或x= 6 5 5 y= 3 5 5 x=- 6 5 5 y=- 3 5 5
∴
=(a 6 5
,5 3 5
)或(-5 6 5
,-5 3 5
)…(12分)5