问题 解答题
已知|
a
|=2,|
b
|=3
,,
a
b
夹角为600
c
=5
a
+3
b
d
=3
a
+k
b
,则当实数k为何值是?
(1)
c
d

(2)
c
d
答案

由题意得

a
b
=|
a
||
b
|cos600=2×3×
1
2
=3

(1)当

c
d
c
d
,则5
a
+3
b
=λ(3
a
+k
b
)
∴3λ=5,且kλ=3∴k=
9
5

(2)当

c
d
c
d
=0
,则(5
a
+3
b
)•(3
a
+k
b
)=0
,∴15
a
2
+3k
b
2
+(9+5k)
a
b
=0
,∴k=-
29
14

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