问题 解答题
解方程
①x2+2x-99=0
②(2x-1)2=x(6x-3)
③4x2-8x+1=0
④(2x-3)2-121=0
x2-2
3
x+3=0

⑥2(x-3)2=9-x2
-3x2-4x+4=0
⑧(x+1)(x-1)+2(x+3)=8
⑨(x+1)2=4(x-2)2
答案

①x2+2x-99=0,

(x+11)(x-9)=0,

x+11=0,x-9=0,

x1=-11,x2=9.

②(2x-1)2=x(6x-3),

(2x-1)2-3x(2x-1)=0,

(2x-1)(2x-1-3x)=0,

2x-1=0,2x-1-3x=0,

x1=

1
2
,x2=-1.

③4x2-8x+1=0,

b2-4ac=(-8)2-4×4×1=48,

x=

48
2×4

x1=

2+
3
2
,x2=
2-
3
2

④(2x-3)2-121=0,

(2x-3+11)(2x-3-11)=0,

2x-3+11=0,2x-3-11=0,

x1=-4,x2=7.

x2-2

3
x+3=0,

(x-

3
2=0,

x-

3
=0,

x1=x2=

3

⑥2(x-3)2=9-x2

2(x-3)2-(x+3)(x-3)=0,

(x-3)(2x-6-x-3)=0,

x-3=0,x-9=0,

-3x2-4x+4=0,

3x2+4x-4=0,

(3x-2)(x+2)=0,

3x-2=0,x+2=0,

x1=

2
3
,x2=-2.

⑧(x+1)(x-1)+2(x+3)=8,

整理得:x2-2x-3=0,

(x-3)(x+1)=0,

x-3=0,x+1=0,

x1=3,x2=-1.

⑨(x+1)2=4(x-2)2

x+1=±2(x-2)

x1=-5,x2=1.

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