问题
解答题
已知G是△ABC的重心，直线EF过点G且与边AB，AC分别交于E，F，
|
答案
由题意可得
| EF |
| AF |
| AE |
| AB |
| AC |
则
| AG |
| 2 |
| 3 |
| AD |
| 2 |
| 3 |
| 1 |
| 2 |
| AB |
| AC |
| 1 |
| 3 |
| AB |
| 1 |
| 3 |
| AC |
| GE |
| AE |
| AG |
| 1 |
| 3 |
| AB |
| 1 |
| 3 |
| AC |
∵E，G，F三点共线 即
| EF |
| GE |
| AB |
| AC |
| α |
| 3 |
| 1 |
| 3 |
解得
| 1 |
| α |
| 1 |
| β |
搜题请搜索小程序“爱下问搜题”
已知G是△ABC的重心，直线EF过点G且与边AB，AC分别交于E，F，
|
由题意可得
| EF |
| AF |
| AE |
| AB |
| AC |
则
| AG |
| 2 |
| 3 |
| AD |
| 2 |
| 3 |
| 1 |
| 2 |
| AB |
| AC |
| 1 |
| 3 |
| AB |
| 1 |
| 3 |
| AC |
| GE |
| AE |
| AG |
| 1 |
| 3 |
| AB |
| 1 |
| 3 |
| AC |
∵E，G，F三点共线 即
| EF |
| GE |
| AB |
| AC |
| α |
| 3 |
| 1 |
| 3 |
解得
| 1 |
| α |
| 1 |
| β |