问题 解答题
计算:
(1)2
3
×3
12

(2)
a5+2a3b2+ab4

(3)
3
1
3
÷(
2
5
2
1
3
)×(4
1
2
5

(4)
a
b
÷
ab•
1
ab
(a、b>0)
答案

(1)原式=(2×3)×

3×12

=6×6

=36;

(2)原式=

a(a4+2a2b2+b4)

=

a(a2+b2)2

=(a2+b2

a

(3)原式=(1×

5
2
×4)×
10
3
×
3
5
×
7
5

=10

14
5

=10×

1
5
70

=2

70

(4)原式=

a
b
1
ab
1
ab

=

1
ab3

=

ab
ab2

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