问题
解答题
脱式计算.
(300+180÷5)×12
600÷[30-(10+5)]
72÷[2×(105-87)].
答案
(1)(300+180÷5)×12
=(300+36)×12
=336×12
=4032;
(2)600÷[30-(10+5)]
=600÷[30-15]
=600÷15
=40;
(3)72÷[2×(105-87)]
=72÷[2×18]
=72÷36
=2.
脱式计算.
(300+180÷5)×12
600÷[30-(10+5)]
72÷[2×(105-87)].
(1)(300+180÷5)×12
=(300+36)×12
=336×12
=4032;
(2)600÷[30-(10+5)]
=600÷[30-15]
=600÷15
=40;
(3)72÷[2×(105-87)]
=72÷[2×18]
=72÷36
=2.