问题
解答题
(1)先化简,再求值:x
(2)解方程:y2+2y-1=0. |
答案
(1)原式=
x |
x |
x |
=2
x |
当x=
1 |
2 |
2
x |
|
2 |
(2)y2+2y-1=0
y2+2y=1
y2+2y+1=1+1
(y+1)2=2
y+1=±
2 |
y+1=
2 |
2 |
∴y1=
2 |
2 |
(1)先化简,再求值:x
(2)解方程:y2+2y-1=0. |
(1)原式=
x |
x |
x |
=2
x |
当x=
1 |
2 |
2
x |
|
2 |
(2)y2+2y-1=0
y2+2y=1
y2+2y+1=1+1
(y+1)2=2
y+1=±
2 |
y+1=
2 |
2 |
∴y1=
2 |
2 |