问题
解答题
(1)先化简,再求值:x
(2)解方程:y2+2y-1=0. |
答案
(1)原式=
-2x
+3x x
=2
,x
当x=
时,1 2
2
=2x
=1 2
.2
(2)y2+2y-1=0
y2+2y=1
y2+2y+1=1+1
(y+1)2=2
y+1=±2
y+1=
,y+1=-2 2
∴y1=
-1,y2=-2
-1.2
(1)先化简,再求值:x
(2)解方程:y2+2y-1=0. |
(1)原式=
-2x
+3x x
=2
,x
当x=
时,1 2
2
=2x
=1 2
.2
(2)y2+2y-1=0
y2+2y=1
y2+2y+1=1+1
(y+1)2=2
y+1=±2
y+1=
,y+1=-2 2
∴y1=
-1,y2=-2
-1.2