问题 填空题 若limn→∞an2+n+1n2+2=1,则实数a的值为______. 答案 ∵limn→∞an2+n+1n2+2=1=limn→∞a+1n+1n21+2n2=a+0+01+0=a,故有 a=1,故答案为 1.