问题
填空题
已知
|
答案
由
=xd
+ya
+zb
,得c
+2e1
+3e2
=x(e3
+e1
+e2
)+y(e3
-e1
+e2
)+z(e3
+e1
-e2
)e3
化为
+2e1
+3e2
=(x+y+z)e3
+(x-y+z)e1
+(x+y-z)e2
,e3
由向量相等条件可得
,解得x+y+z=1 x-y+z=2 x+y-z=3
,x= 5 2 y=- 1 2 z=-1
故答案为
,-5 2
,-1.1 2