问题
解答题
计算: (1)
(2)
|
答案
(1)
=(1+2i)2+3(1-i) 2+i
=-3+4i+3-3i 2+i
=i 2+i
=i(2-i) (2+i)(2-i)
=i(2-i) 5
+1 5
i.2 5
(2)
=1-
i3 (
+i)23
=(
+i)(-i)3 (
+i)23
=-i
+i3
=-i(
-i)3 (
+i)(3
-i)3
=-(-i)(
-i)3 4
-1 4
i.3 4