问题
填空题
在△ABC中,E为AC上一点,
|
答案
在△ABC中,
=AC
-BC
=BA
-a
,b
∵
=AE 1 2
∴EC
=AE 1 3
=AC
(1 3
-a
),b
=BE
+BA
=AE
+a
(1 3
-a
)=b 1 3
+a 2 3 b
故答案为:1 3
+a 2 3 b
在△ABC中,E为AC上一点,
|
在△ABC中,
=AC
-BC
=BA
-a
,b
∵
=AE 1 2
∴EC
=AE 1 3
=AC
(1 3
-a
),b
=BE
+BA
=AE
+a
(1 3
-a
)=b 1 3
+a 2 3 b
故答案为:1 3
+a 2 3 b