点G是△ABC的重心,
|
∵点G是△ABC的重心,∴
=AG 1 3
+AB 1 3
,AC
∴AG2=
(AB2+AC2+21 9
•AB
)=AC
(AB2+AC2-4)≥1 9
(2AB×AC-4)1 9
∵
•AB
=-2,∴AB×AC×COSA=-2,∴AB×AC=4.AC
∴AG2≥4 9
故填
.2 3
点G是△ABC的重心,
|
∵点G是△ABC的重心,∴
=AG 1 3
+AB 1 3
,AC
∴AG2=
(AB2+AC2+21 9
•AB
)=AC
(AB2+AC2-4)≥1 9
(2AB×AC-4)1 9
∵
•AB
=-2,∴AB×AC×COSA=-2,∴AB×AC=4.AC
∴AG2≥4 9
故填
.2 3