问题
选择题
曲线y=
|
答案
∵y=
-1 x
,x
∴y'=-
-1 x2
x-1 2 1 2
∴y=f(x)在点P(4,-
)处的切线斜率是k=-7 4
,5 16
∴曲线y=f(x)在点P(4,-
)处的切线方程为:y+7 4
=-7 4
(x-4),5 16
即5x+16y+8=0.
故选A.
曲线y=
|
∵y=
-1 x
,x
∴y'=-
-1 x2
x-1 2 1 2
∴y=f(x)在点P(4,-
)处的切线斜率是k=-7 4
,5 16
∴曲线y=f(x)在点P(4,-
)处的切线方程为:y+7 4
=-7 4
(x-4),5 16
即5x+16y+8=0.
故选A.