问题
填空题
若
|
答案
=BD
-CD
=(2CB
-e1
)-(e2
+3e1
)=2e2
-4e1 e2
因为A,B,D三点共线,
所以
=kAB
,已知BD
=2AB
+ke1
,e2
=2BD
-4e1 e2
所以k=-4
故答案为:-4
若
|
=BD
-CD
=(2CB
-e1
)-(e2
+3e1
)=2e2
-4e1 e2
因为A,B,D三点共线,
所以
=kAB
,已知BD
=2AB
+ke1
,e2
=2BD
-4e1 e2
所以k=-4
故答案为:-4