问题
解答题
计算下列各题: (1)(5m3n2)2•(-2m2)3•(-n3)4; (2)(π-3)0+(-0.125)2011×82011; (3)(2am-3bn)(3an+5bm); (4)(
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答案
(1)原式=25m6n4•(-8m6)•n12=-200m12n16;
(2)原式=1+(-0.125×8)2009=1-1=0;
(3)原式=6am+n+10ambm-9anbn-15bm+n;
(4)原式=
x2-1 9
y2-(9 16
x2-1 9
xy+1 2
y2)=9 16
x2-1 9
y2-9 16
x2+1 9
xy-1 2
y2=-9 16
y2+9 8
xy.1 2