问题
解答题
计算: (1)
(2)(
|
答案
(1)原式=
-2a (a+3)(a-3) a+3 (a+3)(a-3)
=a-3 (a+3)(a-3)
=
;1 a+3
(2)原式=
•b-a ab ab (a+b)(a-b)
=-
•a-b ab ab (a+b)(a-b)
=-
.1 a+b
计算: (1)
(2)(
|
(1)原式=
-2a (a+3)(a-3) a+3 (a+3)(a-3)
=a-3 (a+3)(a-3)
=
;1 a+3
(2)原式=
•b-a ab ab (a+b)(a-b)
=-
•a-b ab ab (a+b)(a-b)
=-
.1 a+b