问题
解答题
设两个非零向量
|
答案
证明:∵
=AB
+e1
,e2
=2BC
+8e1
,e2
=3(CD
-e1
)e2
又
=BD
+BC
=2CD
+8e1
+3(e2
-e1
)=5(e2
+e1
)=5e2 AB
∴
与AB
共线.BD
∴即A,B,D三点共线.
设两个非零向量
|
证明:∵
=AB
+e1
,e2
=2BC
+8e1
,e2
=3(CD
-e1
)e2
又
=BD
+BC
=2CD
+8e1
+3(e2
-e1
)=5(e2
+e1
)=5e2 AB
∴
与AB
共线.BD
∴即A,B,D三点共线.