问题
解答题
先化简(
|
答案
原式=[
-x+2 x(x-2)
]•x-1 (x-2)2 x 4-x
=
•(x+2)(x-2)-x(x-1) x(x-2)2 x 4-x
=x2-4-x2+x (x-2)2(4-x)
=-
,1 (x-2)2
当x=1时,原式=-
=-1.1 (1-2)2
先化简(
|
原式=[
-x+2 x(x-2)
]•x-1 (x-2)2 x 4-x
=
•(x+2)(x-2)-x(x-1) x(x-2)2 x 4-x
=x2-4-x2+x (x-2)2(4-x)
=-
,1 (x-2)2
当x=1时,原式=-
=-1.1 (1-2)2