问题
解答题
(1)先化简,再求值:(1+
(2)解分式方程:
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答案
(1)原式=
•x-1 x-2
=(x+2)(x-2) (x-1)2
,x+2 x-1
当x=-5时,原式=
=-5+2 -5-1
;1 2
(2)去分母得:3(x-1)+x+1=6,
去括号得:3x-3+x+1=6,
解得:x=2,
经检验x=2是分式方程的解.
(1)先化简,再求值:(1+
(2)解分式方程:
|
(1)原式=
•x-1 x-2
=(x+2)(x-2) (x-1)2
,x+2 x-1
当x=-5时,原式=
=-5+2 -5-1
;1 2
(2)去分母得:3(x-1)+x+1=6,
去括号得:3x-3+x+1=6,
解得:x=2,
经检验x=2是分式方程的解.