问题
填空题
若x+y+z=6，xy+yz+zx=11，xyz=6，则
|
答案
∵
| x |
| yz |
| y |
| zx |
| z |
| xy |
| x2+y2+z2 |
| xyz |
| (x+y+z)2-2(xy+yz+xz) |
| xyz |
∴原式=
| 62-2×11 |
| 6 |
| 14 |
| 6 |
| 7 |
| 3 |
故答案是：
| 7 |
| 3 |
搜题请搜索小程序“爱下问搜题”
若x+y+z=6，xy+yz+zx=11，xyz=6，则
|
∵
| x |
| yz |
| y |
| zx |
| z |
| xy |
| x2+y2+z2 |
| xyz |
| (x+y+z)2-2(xy+yz+xz) |
| xyz |
∴原式=
| 62-2×11 |
| 6 |
| 14 |
| 6 |
| 7 |
| 3 |
故答案是：
| 7 |
| 3 |