问题
填空题
已知an=
|
答案
∵an=
=2 n 1 n+1 1 n
-2 n
=n n+1
,2n+2-n2 n2+n
∴lim n→∞
=2n+2-n2 n2+n lim n→∞
=-1.
+2 n
-12 n2 1+ 1 n
故答案为:-1.
已知an=
|
∵an=
=2 n 1 n+1 1 n
-2 n
=n n+1
,2n+2-n2 n2+n
∴lim n→∞
=2n+2-n2 n2+n lim n→∞
=-1.
+2 n
-12 n2 1+ 1 n
故答案为:-1.