问题 解答题
对于正数x,规定f(x)=
x2
1+x2
,如f(1)=
1
1+1
=
1
2

(1)计算f(2)=______;f(
1
2
)=______;f(2)+f(
1
2
)=______;f(3)+f(
1
3
)=______;…
(2)猜想f(x)+f(
1
x
)=______,请予以证明.
答案

(1)f(2)=

4
1+4
=
4
5
;f(
1
2
)=
1
4
1+
1
4
=
1
5
,f(2)+f(
1
2
)=
4
5
+
1
5
=1;f(3)+f(
1
3
)=
9
1+9
+
1
9
1+
1
9
=
9
10
+
1
10
=1;

(2)猜想f(x)+f(

1
x
)=1,

理由为:f(x)+f(

1
x
)=
x2
1+x2
+
1
x2
1+
1
x2
=
x2+1
x2+1
=1.

故答案为:(1)

4
5
1
5
;1;1;(2)1

不定项选择
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