问题
填空题
计算: (1)
(2)
(3)
(4)
(5)(ab-b2)÷
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答案
(1)原式=
;n m2
(2)原式=
•3xy 4a
=1 6xy2
;1 8ay
(3)原式=
•4 (a+1)(a-1)
=a-1 6a
=2 3a(a+1)
;2 3a2+3a
(4)原式=
•(x+y)(x-y) x
=(x+y)2=x2+2xy+y2;x(x+y) x-y
(5)原式=b(a-b)•
=b.a+b (a+b)(a-b)
故答案为
;n m2
;1 8ay
;x2+2xy+y2;b.2 3a2+3a