问题 单项选择题

如果两个四位数的差等于8921,那么就说这两个四位数组成一个数对,问这样的数对共有多少个

A.80

B.79

C.83

D.81

答案

参考答案:B

解析: 从两个极端来考虑这个问题:最大为9999-1078=8921,最小为9921-1000=8921,所以共有9999-9921+1=79个,或1078-1000+1=79个。故应选择B。

写句子

按要求写句子。  

1.我为爸爸找到了病因,心里很高兴。(改为反问句)  

                                                                                                                                                     

2.爸爸的咳嗽和东南风好像真有联系。(改为否定句) 

                                                                                                                                                         

3.妈妈对我说:“今天晚上我有应酬,你和爸爸先吃饭吧!”(改为转述句) 

                                                                                                                                                      

4.难道你不用蜡烛就不行吗?(改为肯定句) 

                                                                                                                                                      

5.只有这个地方是安全的。(改为否定句)    

                                                                                                                                                       

6.晚上这么黑,多点支蜡烛也好嘛。(改为反问句) 

                                                                                                                                                         

7.谁能相信这是大自然的现实,而不是大胆的梦幻呢?(改为陈述句) 

                                                                                                                                                    

8.汽车跑得很快。(改为夸张句) 

                                                                                                                                                    

9.爸爸微笑着对小明说:“我今天下午要出差,告诉你妈妈我不回家吃饭了。”(改为转述句)

                                                                                                                                                         

10.他会灵活运用词语。  他每次作文都写得不错。(合并为一句话)

                                                                                                                                                    

单项选择题