问题 解答题
用递等式计算
315-135÷9
105-13×6+57(45+240)÷(20-5)
答案

(1)315-135÷9,

=315-15,

=300;

(2)105-13×6+57,

=105-78+57,

=27+57,

=84;

(3)(45+240)÷(20-5),

=285÷15,

=19.

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