问题 选择题
给出下面四个式子:
lim
x→2
x2-4
x-2

lim
x→∞
4x2+3
6x2-5

lim
x→+∞
(
x2+2
-
x2-2
)

lim
x→2
3x-1
-1
x-1
-1

其中极限等于
2
3
的有(  )
A.0个B.1个C.2个D.3个
答案

∵①

lim
x→2
x2-4
x-2
=
lim
x→2
(x+2)
=4

lim
x→∞
4x2+3
6x2-5
=
lim
x→∞
4+
3
x2
6-
5
x2
=
2
3

lim
x→+∞
(
x2+2
-
x2-2
)=
lim
x→+∞
4
2+x2+
x2-2
=0

④x-1=t6,则

lim
x→2
3x-1
-1
x-1
-1
=
lim
t→1
t2-1
t3-1
=
lim
t→1
t+1
t2+t+1
=
2
3

故选C

单项选择题 A2型题
单项选择题