问题
解答题
求
|
答案
lim n→∞ (n2+1)+(n2+2)+…+(n2+n) n(n-1)(n-2)
=lim n→∞ n3+(1+2+3+…+n) n3-3n2+2n
=lim n→∞ n3+ n2+n 2 n3-3n2+2n
=1．
搜题请搜索小程序“爱下问搜题”
求
|
lim n→∞ (n2+1)+(n2+2)+…+(n2+n) n(n-1)(n-2)
=lim n→∞ n3+(1+2+3+…+n) n3-3n2+2n
=lim n→∞ n3+ n2+n 2 n3-3n2+2n
=1．