问题
填空题
计算:
|
答案
∵
(2n-lim n→∞
)=4n2+2n-1 2n+2 lim n→∞ 4n2+4n-4n2-2n+1 2n+2
=lim n→∞
=2n+1 2n+2 lim n→∞
=11+ 1 2n 1+ 1 n
故答案为:1
计算:
|
∵
(2n-lim n→∞
)=4n2+2n-1 2n+2 lim n→∞ 4n2+4n-4n2-2n+1 2n+2
=lim n→∞
=2n+1 2n+2 lim n→∞
=11+ 1 2n 1+ 1 n
故答案为:1