问题
填空题
|
答案
设A=
+1 n2+1
+2 n2+1
+…+3 n2+1
=2n n2+1
=1+2+3+…+2n n2+1 2n2+n n2+1
所以
(lim n→∞
+1 n2+1
+2 n2+1
+…+3 n2+1
)=2n n2+1
A=lim n→∞ lim n→∞
=22n2+n n2+1
故答案为2．
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|
设A=
+1 n2+1
+2 n2+1
+…+3 n2+1
=2n n2+1
=1+2+3+…+2n n2+1 2n2+n n2+1
所以
(lim n→∞
+1 n2+1
+2 n2+1
+…+3 n2+1
)=2n n2+1
A=lim n→∞ lim n→∞
=22n2+n n2+1
故答案为2．