问题 解答题
化简:
(1)(
3
-
2
)
0
-(-
1
2
)
-2

(2)(m-3n)-2•(2m-2n-3-2
(3)a-2b2•(-2a2b-2-2÷(a-4b2
(4)(2m2n-33(-mn-2-2
答案

(1)(

3
-
2
0-(-
1
2
-2

=1-4

=-3;

(2)(m-3n)-2•(2m-2n-3-2

=m6n-2•2-2m4n6

=

1
4
m6+4n-2+6

=

1
4
m10n4

(3)a-2b2•(-2a2b-2-2÷(a-4b2

=a-2b2•(-2)-2a-4b4÷(a-4b2

=

1
4
a-2-4-(-4)b2+4-2

=

1
4
a-2b4

=

b4
4a2

(4)(2m2n-33(-mn-2-2

=23m6n-9(-m)-2n4

=8m6-2n-9+4

=8m4n-5

=

8m4
n5

名词解释
单项选择题 A3/A4型题