问题 填空题
lim
x→0
(
1
x2-x
-
2
x2-2x
)
=______.
答案

lim
x→0
(
1
x2-x
-
2
x2-2x
)=
lim
x→0
[
1
x(x-1)
-
2
x(x-2)
]

=

lim
x→0
x-2-2x+2
x(x-1)(x-2)

=

lim
x→0
-1
(x-1)(x-2)

=-

1
2

故答案为:-

1
2

单项选择题 A1/A2型题
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