问题
填空题
|
答案
∵
[x(lim x→-∞
-x2+1
)]=x2-1
[lim x→-∞
]2x
+x2+1 x2-1
=lim x→-∞
=-2
+1 + 1 x 2 1- 1 x 2
=-1-2 1+1
故答案为：-1
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|
∵
[x(lim x→-∞
-x2+1
)]=x2-1
[lim x→-∞
]2x
+x2+1 x2-1
=lim x→-∞
=-2
+1 + 1 x 2 1- 1 x 2
=-1-2 1+1
故答案为：-1
