问题
填空题
|
答案
原式=lim n→∞ (
-n)(n2+2n
+n)n2+2n
+nn2+2n
=lim n→∞ 2n
+nn2+2n
=lim n→∞ 2
+11+ 2 n
=1．
故答案是1．
搜题请搜索小程序“爱下问搜题”
|
原式=lim n→∞ (
-n)(n2+2n
+n)n2+2n
+nn2+2n
=lim n→∞ 2n
+nn2+2n
=lim n→∞ 2
+11+ 2 n
=1．
故答案是1．
