问题 解答题
用递等式计算(能简算的要简算)
①(
1
4
+
1
2
)÷(1-
3
8
×
3
4

②3.2×1.25+4.8×1
1
4

③[(5
2
3
-4
3
4
)÷1
5
6
]×25%
15
16
+(
7
16
-
1
4
)÷
1
2
答案

①(

1
4
+
1
2
)÷(1-
3
8
×
3
4
);

=

3
4
÷(1-
9
32
),

=

3
4
×
32
23

=1

1
23

②3.2×1.25+4.8×1

1
4

=3.2×1.25+4.8×1.25,

=1.25×(3.2+4.8),

=1.25×8,

=10;

③[(5

2
3
-4
3
4
)÷1
5
6
]×25%,

=[

11
12
÷
11
6
1
4

=[

11
12
×
6
11
1
4

=

1
2
×
1
4

=

1
8

15
16
+(
7
16
-
1
4
)÷
1
2

=

15
16
+
3
16
÷
1
2

=

15
16
+
3
16
×2,

=

15
16
+
3
8

=1

5
16

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