问题
解答题
计算: (1)-
(2)|1-
(3)25x2-36=0 (4)(x+3)3=27. |
答案
(1)原式=-6+
+3=-3+3 2
=-3 2
;3 2
(2)原式=
-1+2
-1=22
-2;2
(3)移向得,25x2=36,
系数化为1得,x2=
,36 25
开方得,x=±
;6 5
(4)开立方得,x+3=
,3 27
解得,x=-3+3=0.
计算: (1)-
(2)|1-
(3)25x2-36=0 (4)(x+3)3=27. |
(1)原式=-6+
+3=-3+3 2
=-3 2
;3 2
(2)原式=
-1+2
-1=22
-2;2
(3)移向得,25x2=36,
系数化为1得,x2=
,36 25
开方得,x=±
;6 5
(4)开立方得,x+3=
,3 27
解得,x=-3+3=0.