问题 解答题

2.1÷〔(3-2)×1〕

7÷4+0.25×3+1×〔1+(6.5-2)÷1〕

〔1+1×(3-1)〕÷1.

答案

(1)2.1÷[(3-2)×1],

=2.1÷(1×1),

=2.1÷1,

=2.1;

(2)7÷4+0.25×3+1×[1+(6.5-2)÷1],

=7÷4+0.25×3+1×[1+4.5÷1],

=7÷4+0.25×3+1×(1+4.5),

=7÷4+0.25×3+1×5.5,

=1.75+0.75+5.5,

=2.5+5.5,

=8;

(3)[1+1×(3-1)]÷1,

=[1+1×2]÷1,

=(1+2)÷1,

=3÷1,

=3.

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