问题
填空题
|
答案
[n(1-lim n→∞
)(1-1 3
)(1-1 4
)…(1-1 5
)]1 n+2
=
(n×lim n→∞
×2 3
×…×3 4
)n+1 n+2
=lim n→∞ 2n n+2
=2．
故答案为：2．
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|
[n(1-lim n→∞
)(1-1 3
)(1-1 4
)…(1-1 5
)]1 n+2
=
(n×lim n→∞
×2 3
×…×3 4
)n+1 n+2
=lim n→∞ 2n n+2
=2．
故答案为：2．