问题
填空题
|
答案
[n•(1-lim n→∞
)(1-1 2
)…(1-1 3
)]n1 n+1
=
( n×lim n→∞
×1 2
×2 3
×…×3 4
)nn n+1
=
(lim n→∞
)nn2 n+1
=
． 1 e
故答案为：
．1 e
搜题请搜索小程序“爱下问搜题”
|
[n•(1-lim n→∞
)(1-1 2
)…(1-1 3
)]n1 n+1
=
( n×lim n→∞
×1 2
×2 3
×…×3 4
)nn n+1
=
(lim n→∞
)nn2 n+1
=
． 1 e
故答案为：
．1 e