问题 解答题
用递等式计算下面各题:
(1)(0.125×8-0.5)×4                   (2)
9
20
÷6+
1
6
×
1
20

(3)
5
6
×0.25+
1
4
×
1
6
                       (4)4-[3.75×(1.2-
1
3
)+
3
4
].
答案

(1)(0.125×8-0.5)×4,

=(1-0.5)×4,

=0.5×4,

=2;

(2)

9
20
÷6+
1
6
×
1
20

=

9
20
×
1
6
+
1
6
×
1
20

=(

9
20
+
1
20
)×
1
6

=

1
2
×
1
6

=

1
12

(3)

5
6
×0.25+
1
4
×
1
6
       

=

5
6
×
1
4
+
1
4
×
1
6

=(

5
6
+
1
6
)×
1
4

=1×

1
4

=

1
4

(4)4-[3.75×(1.2-

1
3
)+
3
4
]

=4-[3.75×(

6
5
-
1
3
)+
3
4
],

=4-[3.75×

6
5
-3.75×
1
3
+0.75],

=4-[4.5-1.25+0.75],

=4-4,

=0.

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