问题 解答题
计算
(1)[5-3
22
63
÷(1
1
4
+2.25×
4
5
)]÷12.5%
(2)[2-(8.25-5
π
2
)×
π
2
]÷0.9
(3)(20
π
2
+12.56-31
π
2
)÷299+(13
2
5
-12.25)×1
4
5

(4)
1
25
×(4.85÷
4
5
-3.6+6.15×3
8
9
)+1.75×(1
2
3
+
1
3
)+5.5.
答案

(1)[5-3

22
63
÷(1
1
4
+2.25×
4
5
)]÷12.5%,

=[5-3

22
63
÷(1
1
4
+
9
5
)]÷12.5%,

=[5-3

22
63
÷
61
20
]÷12.5%,

=[5-

4220
3843
]÷12.5%,

=

14995
3843
×8,

=

119960
3843

(2)[2-(8.25-5

π
2
)×
π
2
]÷0.9,

=[2-1.68×1.57]÷0.9,

=[2-2.6376]÷0.9,

=[-0.6376]÷0.9,

=-

63790
90000

(3)(20

π
2
+12.56-31
π
2
)÷299+(13
2
5
-12.25)×1
4
5

=(20

π
2
+12.56-31
π
2
)÷299+1.15×1
4
5

=(12.56-11)÷299+2.07,

=1.56÷299+2.07,

=

3
575
+2
7
100

=2

173
2300

(4)

1
25
×(4.85÷
4
5
-3.6+6.15×3
8
9
)+1.75×(1
2
3
+
1
3
)+5.5,

=

1
25
×(
97
16
-3.6+
287
12
)+1.75×2+5.5,

=

1
25
×(
97
16
-3
3
5
+
287
12
)+1.75×2+5.5,

=

1
25
×(
197
80
+
287
12
)+3.5+5.5,

=

1
25
×
6331
80
+9,

=

6331
2000
+9,

=9

6331
2000

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