问题
填空题
方程:
|
答案
∵
+x-a-b c
+x-b-c a
=3x-c-a b
⇒
-x c
-1+a+b c
-x a
-1+b+c a
-x b
-1=0c+a b
x(
+1 c
+1 a
)-(a+b+c)(1 b
+1 a
+1 b
)=01 c
[x-(a+b+c)](
+1 a
+1 b
)=01 c
∵
+1 a
+1 b
是一元一次方程的系数1 c
∴必然是
+1 a
+1 b
≠01 c
∴只能是x=a+b+c
故答案为a+b+c