问题
解答题
用递等式计算.
360+612÷12128×68-36182÷14+27(648+245)×12.
答案
(1)360+612÷12,
=360+102,
=462;
(2)128×68-36,
=8704-36,
=8668;
(3)182÷14+27,
=13+27,
=40;
(4)(648+245)×12,
=893×12,
=10716.
用递等式计算.
360+612÷12128×68-36182÷14+27(648+245)×12.
(1)360+612÷12,
=360+102,
=462;
(2)128×68-36,
=8704-36,
=8668;
(3)182÷14+27,
=13+27,
=40;
(4)(648+245)×12,
=893×12,
=10716.